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10 / CHAPTER 05

Momentum in a flowing control volume

Calculate jet reactions, bends, and support loads.

Fluid Mechanics: original course diagram
A visual model for this course. Read it as a prompt for the assumptions behind the chapter.

ANCHOR EQUATION

Control-volume momentum

ΣF=ṁvout−vin

In symbols: ΣF = ṁ(vout − vin)

The force on a jet, bend, or nozzle follows from momentum flux change.

Bernoulli is an energy balance along an ideal streamline

Pressure, kinetic energy per volume, and gravitational potential per volume can exchange as a fluid moves. Bernoulli is powerful because it compresses a force-and-energy argument, but every omitted loss is an assumption.

Derive the ideal relation

For a small fluid parcel of volume dV moving distance ds along a streamline, pressure work is (p₁ − p₂)dV, gravity work is ρg(z₁ − z₂)dV, and kinetic-energy change is ½ρdV(v₂² − v₁²). Set work equal to kinetic-energy change, divide by dV, and rearrange: p + ½ρv² + ρgz = constant. Add pump head and subtract losses for real systems.

Water exits a reservoir at p₁ = p₂ atmospheric, v₁ ≈ 0, and drops 2 m to a nozzle. Ideal speed satisfies ½ρv² = ρg(2), so v = √39.24 = 6.26 m/s.

Viscosity breaks the constant

Pipe friction, valves, bends, turbulence, and pumps add or remove mechanical energy. Bernoulli can still be used between points if a measured or modeled head-loss term is included.

Work it: A nozzle is 1.5 m above a reservoir and has 0.8 m head loss. Find ideal and corrected exit speeds, assuming both points are atmospheric and reservoir speed is negligible.