PHYSICS / COURSE NAVIGATOR
← Back to course

02 / CHAPTER 04

Newton’s third law

Pair interaction forces across bodies without canceling forces on one body.

Dynamics: original course diagram
A visual model for this course. Read it as a prompt for the assumptions behind the chapter.

ANCHOR EQUATION

Interaction pair

FAB=−FBA

In symbols: FAB = −FBA

Newton’s third-law forces act on different bodies.

Third-law pairs live on different diagrams

When hand A pushes box B, B pushes A with equal magnitude and opposite direction. The pair cannot cancel in the equation for B because A’s force acts on A, not on B.

Use an interaction graph

For an interaction between A and B, Newton’s third law gives F_AB = −F_BA. In a system containing both objects, the pair sums to zero internally. In a free-body diagram of B alone, only F_AB appears; external forces on B determine its acceleration.

A 70 kg person pushes a 10 kg cart with 35 N. The person’s acceleration from that interaction alone is 35/70 = 0.50 m/s² backward; the cart’s is 35/10 = 3.5 m/s² forward. Equal force does not imply equal acceleration because masses differ.

Action–reaction is not cause followed by delay

The forces arise simultaneously from the same contact interaction. Weight and normal force are not a third-law pair because they act on the same object; the partner of Earth’s gravitational pull on the book is the book’s gravitational pull on Earth.

Work it: For a swimmer pushing water backward, draw separate diagrams for swimmer and water. Identify the third-law pair and predict which object has the larger acceleration.