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07 / CHAPTER 04

Gauss’s law

Exploit symmetry to calculate electric fields.

Electricity & Magnetism: original course diagram
A visual model for this course. Read it as a prompt for the assumptions behind the chapter.

ANCHOR EQUATION

Gauss’s law

∮E·dA=Qencε0

In symbols: ∮E·dA = Qenc/ε₀

Symmetry turns a field integral into a charge-enclosure relation.

Gauss’s law counts enclosed source

Electric flux measures how much field pierces a surface. Gauss’s law is always true, but it becomes a calculation shortcut only when symmetry makes E constant or predictably oriented over the surface.

Use a closed-surface balance

The flux through a small area is E·dA. Summing over a closed surface gives ∮E·dA = Q_enc/ε₀. For a spherical point-charge surface, E is constant and radial, so E(4πr²) = Q/ε₀ and E = Q/(4πε₀r²), recovering Coulomb’s law.

A uniformly charged sphere with total Q has outside field as if all charge were at its center. Inside a spherical shell, Q_enc = 0 and symmetry gives E = 0, even though the shell’s nearby charge is not absent.

Flux can vanish with nonzero field

A uniform field through a closed cube has equal entering and leaving flux, so net flux is zero while E is not. Enclosed charge, not field magnitude alone, controls net flux.

Work it: Use a cylindrical Gaussian surface around an infinite line charge λ. Derive E = λ/(2πε₀r) and identify the symmetry assumption.