PHYSICS / COURSE NAVIGATOR
← Back to course

04 / CHAPTER 09

Newtonian gravity

Use inverse-square interaction and distinguish weight from mass.

Rotation & Gravitation: original course diagram
A visual model for this course. Read it as a prompt for the assumptions behind the chapter.

ANCHOR EQUATION

Newtonian gravity

F=GMmr2

In symbols: F = GMm/r²

Gravity is an inverse-square interaction between two masses.

Gravity falls as inverse square

Newtonian gravity between point masses weakens because the same influence spreads over spherical area 4πr². The force is attractive and proportional to both masses.

Combine field and mass

The gravitational field of mass M at distance r has magnitude g(r) = GM/r². A test mass m experiences F = mg(r) = GMm/r². Here G = 6.674×10⁻¹¹ N·m²/kg², M and m are masses, and r is center-to-center separation.

At Earth’s surface, using GM ≈ 3.986×10¹⁴ m³/s² and r = 6.37×10⁶ m gives g = GM/r² ≈ 9.82 m/s². At twice Earth’s radius, g becomes one quarter, 2.46 m/s².

Weight is local; mass is not

The approximation treats Earth as spherical and the object as small compared with r. Close to an irregular body, altitude, latitude, and local mass distribution alter g.

Work it: Calculate the gravitational force between 1000 kg and 2000 kg separated by 10 m. Compare it with the weight of the smaller mass on Earth.